A pile of coal is transported in three days. One fifth of it is transported in the first day. The ratio of the second day to the third day is 5:8. The third day is 38 tons more than the first day

A pile of coal is transported in three days. One fifth of it is transported in the first day. The ratio of the second day to the third day is 5:8. The third day is 38 tons more than the first day


On the second and third day of the games, 1-1 / 5 = 4 / 5
(4 / 5) × [8 / (5 + 8)] = 32 / 65 on the third day
Total amount: 38 ÷ (32 / 65-1 / 5) = 130 tons



A pile of coal, 500 tons in the first day, just carried away 1 / 4 of this pile of coal, the next day and the total mass ratio of this pile of coal is 3:8, how many tons in the next day?


The details of the problem are not clear. Is it 3 / 8 of the whole pile of coal transported on the second day or the remaining 3 / 8 after the first day?
If the former: the second day (500t * 4) * 3 / 8 = 750t
If it is the latter, it will be (500t * 3) * 3 / 8 = 562.5t on the second day