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There are 30 tons of fish in warehouse A and 40 tons of fish in warehouse B of a fishing ground. It is necessary to transport 80 tons of fish to these two warehouses, so that the amount of fish in warehouse A is 1.5 times of that in warehouse B. how many tons of fish should be transported to warehouse A and warehouse B respectively?
The fish transported to warehouse A is x tons, and the fish transported to warehouse B is (80-x) tons
30+X=1.5（80-X+40）
The solution is x = 60
Then 80-x = 80-60 = 20
A: 60 tons of fish are transported to warehouse A and 20 tons to warehouse B
There are 360 tons of goods in the two warehouses of Party A and Party B. after Party A has transported 40 tons to Party B, Party B has 10 tons more than Party A. how many tons of the original goods in the warehouse of Party A and Party B?
A: 215 tons
B: 145 tons
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