Party A, Party B and Party C transport a batch of goods. Party A transports 2 / 5 of the total number of goods, 50% more than Party C. Party A and Party B transport 152 tons in total. At this time, the ratio of the remaining goods to the transported goods is 1:9. How many tons of this batch of goods?

Party A, Party B and Party C transport a batch of goods. Party A transports 2 / 5 of the total number of goods, 50% more than Party C. Party A and Party B transport 152 tons in total. At this time, the ratio of the remaining goods to the transported goods is 1:9. How many tons of this batch of goods?

Let's assume that the total quantity of the goods is x tons
Party a transported 2 / 5x tons, and Party C transported (2 / 5x) / (1 + 50%) tons, i.e. 4 / 15x tons
The equation (x-152-4 / 15x) / (152 + 4 / 15x) = 1 / 9 is obtained
The solution is x = 240 tons

A batch of goods has been transported by three vehicles of Party A, Party B and Party C. vehicle a has transported 40% of the total, while vehicle B has transported 60% of vehicle C. vehicle a has transported 28 tons more than vehicle B,
How many tons are there in total?

Let's suppose that the goods have X tons
So:
A transported 40x% tons, B transported 40x% - 28 tons, C transported x-40x% - (40x% - 28) tons
So: 40x% - 28 = [x-40x% - (40x% - 28)] × 60%
0.4x-28=（0.2x+28）×0.6
0.4x-28=0.12x+16.8
0.28x=44.8
x=160
So this shipment is 160 tons