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A factory has 360kg type a raw material and 290kg type B raw material. It plans to use these two raw materials to produce 50 pieces of products a and B. It is known that 9kg type a raw material and 3kg type B raw material are needed to produce a product a; 4kg type a raw material and 10kg type B raw material are needed to produce a product B. (1) suppose to produce X type a products, write out the inequality group that x should satisfy; (2) what kinds of products do you have Production plan? Please list them one by one
(1) Suppose we produce X pieces of a kind of products, according to the meaning of the question: 9x + 4 (50 − x) ≤ 3603x + 10 (50 − x) ≤ 290 (2) the inequality in solution (1) is: 30 ≤ x ≤ 32, so there are three schemes, when a is 30, B is 20. When a is 31, B is 19, when a is 32, B is 18
A factory has 360kg type a raw material and 290kg type B raw material. It plans to use these two raw materials to produce 50 pieces of products a and B. It is known that 9kg type a raw material and 3kg type B raw material are needed to produce a product a, 4kg type a raw material and 10kg type B raw material are needed to produce a product B,
Let X be a production of X parts, and write out the system of inequalities that x should satisfy
If x is an integer, what kind of production plan is there
9x+4(50-x)≤360
3x+10(50-x)≤290
The solution is: 30 ≤ x ≤ 32
Because x is an integer
So x = 30, 31, 32
So there are three options: 1) a 30 pieces, B 20 pieces
2) A 31 pieces, B 19 pieces
3) A 32 pieces, B 18 pieces
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