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There is a batch of goods, if it takes 36 hours for Party A to carry, if it takes 45 hours for Party B, it is known that Party A transports 1.5 tons more per hour than Party B, how many tons of goods are there? A and B have two drainage ports. The waterway is 252 meters long. A ship sails from a to B and arrives in 9 hours downstream. From B to a, it arrives in 14 hours upstream. Find the ship's velocity in still water and current velocity (both equations are arithmetical) (best arithmetical)
Efficiency a 1 / 36. Efficiency B 45
1.5÷（1/36-1/45)
=1.5÷1/180
=270
Let X be the velocity of water flow
252÷9-252÷14=2x
28-18=2x
x=5
252÷9-5=23
The speed of the ship in still water is 23 km / h and the current speed is 5 km / h
A group of goods were delivered to the teams a and B according to 5:3. The team transported 48 tons to complete the 45 of the team's task and transferred them. The rest were transported by team B. how many tons did the second team carry?
3 + 5 = 848 ﹣ 45 ﹣ 58-48 = 60 ﹣ 58-48 = 96-48 = 48 (tons) a: Team B transported 48 tons
For a manuscript, Party A and Party B work together for 5 hours. Party A's work efficiency is equivalent to 80% of Party B's. If the manuscript is completed by Party B, how many hours will it take?
Determinant
Let B be X
x+80%x=1/5
x=1/9
1 / (1 / 9) = 9 (hours)
The arithmetic is
Party A and Party B need to work for 5 hours. When Party B works for 5 hours, Party A's work efficiency is converted into Party B's 80% X5 = 4 hours
So it's all done by B = 5 + 4 = 9 hours
For a manuscript, Party A and Party B work together for 6 hours and party a work alone for 10 hours?
The working efficiency of Party A and Party B is 1 / 6
That is, the efficiency of 10 / 60 A is 6 / 60
The efficiency of B is 4 / 60
The ratio of a to B is 3:2
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