Party A and Party B transport a batch of goods. Party A carries 20 pieces more than 1 / 3 of this batch of goods, and Party B carries 24 pieces more than half of Party A How many pieces are there in this shipment?

Suppose there are x pieces in total
（1/3X+20）+（1/3X+20）*1/2+24=X
1/3X+20+1/6X+10+24=X
1/2X+54=X
X=108
A: there are 108 pieces in total

There are two piles a and B. It is known that pile a is 18 tons more than pile B. If pile B transports 90% of it, it is equal to the quantity transported by pile A. at this time, the quantity ratio of pile B and pile a is 1:3. How many tons of goods are transported by each pile?

Suppose B has x tons, then a has x + 18 tons, (1-90%) x: (x + 18-90% x) = 1:3, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & 0.1X + 18 = 0.3x, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp

A batch of goods, a car to transport it 1 / 4 more than 5 tons, B car than a car to transport 3 / 5 less than 2 tons, so just finished, how many tons of this batch of goods? Fast ah

B shipped all the following:
(1/4+5)x3/5-2
=3/20+3-2
=3/20+1
So all of them are:
(1+5)÷(1-3/20-1/4)
=6÷12/20
=10 (ton)

Two cars carry 136 tons of goods at the same time. It takes 3.5 days for car a to transport, which is 20 tons more than that of car B in 7.5 days. How many tons does car B transport per day on average

On average, vehicle B transports x tons per day
7.5x+20=136*3.5
x=60.8
The average daily transport capacity of vehicle B is 60.8 tons

Party A and Party B transport a batch of goods. Party A carries 20 pieces more than 1 / 3 of this batch of goods, and Party B carries 24 pieces more than half of Party A How many pieces are there in this shipment?