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There are three vehicles in the fleet of a factory to organize the circulation transportation for the five workshops a, B, C, D and E. as shown in the figure, the number marked is the number of loading and unloading workers required in each workshop. In order to save manpower and let some loading and unloading workers follow the car, the minimum arrangement is as follows______ There are three stevedores to meet the needs of each workshop
There are 3 loaders in each workshop, 3 × 5 = 15 persons in total, 3 persons in each vehicle, 3 × 3 = 9 persons in total, which can save 15-9 = 6 persons. At this time, there are 3 persons in a, 2 persons in B, 4 persons in C, 0 persons in D and 5 persons in E. then there are 2 persons in a, B, C and E, 2 persons in each vehicle, which can save 2 × 4-2 × 3 = 2 persons
A and B trucks transport 99 tons of cement together. Nine times each transport is just finished. A truck transports 5 tons each time, B truck transports how many tons each time?
The total quantity of 9 times transportation by a car = 5 × 9 = 45 (tons)
Total amount transported by vehicle B = 99-45 = 54 (tons)
The quantity transported by vehicle B each time = 54 / 9 = 6 (T)
A: Vehicle B transports 6 tons each time
A truck transports 1 / 5 ton of cement in 10 hours, just 2 / 7 of this batch of cement. How many tons of this batch of cement in total
A truck transports 1 / 5 ton of cement in 10 hours, which just transports 2 / 7 of this batch of cement,
This batch of cement is 1 / 5 (2 / 7) = 7 / 10 tons
Using a truck to transport a batch of cement, we have transported 6 times, which is exactly 2 / 5 of this batch of cement. How many times will we have to transport the rest?
Nine more deliveries
Because 6 times of transportation is exactly 2 / 5 of this batch of cement, it can be assumed that a total of x times of transportation is needed to complete the transportation
From the meaning of the title can be listed 6 / x = 2 / 5, x = 15 times
It has been transported 6 times, so 15 - 6 = 9 times, and it needs 9 times to complete
This kind of question in the examination depends on what type of question, such as multiple-choice questions, a little proportion can get the result, 6 times run 2 / 5, that is to say, each run 3 times, a total of 5, that is, a total of 15, and then a reduction is done
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