There are 12 agricultural vehicles and 6 agricultural vehicles in the two warehouses of a company, Now we need to transfer 10 vehicles to a county and 8 vehicles to B county. It is known that the freight of one agricultural vehicle from a warehouse to a county and B county is 40 yuan and 80 yuan respectively, and the freight of one agricultural vehicle from B warehouse to a county and B county is 30 yuan and 50 yuan respectively (1) If x farm vehicles are transferred from warehouse A to county a, please complete the following table with the algebraic formula of X: 12 in warehouse A and 6 in warehouse B County A: 10 x 8 vehicles in County B (2) Please use the algebraic expression of X to express the total freight required for the whole shipment (3) If the total freight is required to be no more than 900 yuan, how many transportation plans are there? (4) How much is the lowest total freight? Too many questions, please help!

There are 12 agricultural vehicles and 6 agricultural vehicles in the two warehouses of a company, Now we need to transfer 10 vehicles to a county and 8 vehicles to B county. It is known that the freight of one agricultural vehicle from a warehouse to a county and B county is 40 yuan and 80 yuan respectively, and the freight of one agricultural vehicle from B warehouse to a county and B county is 30 yuan and 50 yuan respectively (1) If x farm vehicles are transferred from warehouse A to county a, please complete the following table with the algebraic formula of X: 12 in warehouse A and 6 in warehouse B County A: 10 x 8 vehicles in County B (2) Please use the algebraic expression of X to express the total freight required for the whole shipment (3) If the total freight is required to be no more than 900 yuan, how many transportation plans are there? (4) How much is the lowest total freight? Too many questions, please help!


1. There are 12 cars in a warehouse, 6 cars in B warehouse, 10 cars in a county, X cars in 10-xb County, 8 cars in 12-x 6 - (10-x) = x-42.40x + 80 (12-x) + 30 (10-x) + 50 (x-4) = 1160-20x3.1160-20x ≤ 900, i.e. x ≥ 13, but according to the meaning of the question, there should be x ≤ 12, so this scheme does not exist. 4



There are 12 agricultural vehicles and 6 agricultural vehicles in a and B warehouses of a company. At present, there are 10 agricultural vehicles to be transferred to a county and 8 to B county. It is known that the transportation cost of one agricultural vehicle from a to a county and B county is 40 yuan and 80 yuan respectively. The transportation cost of one agricultural vehicle from B to a county and B county is 30 yuan and 50 yuan respectively, And the freight is just enough


First of all, minimize the use of 80 yuan freight. Then, warehouse a will send 10 vehicles needed by county a first, and the remaining 2 vehicles will go to county B. all 6 vehicles in warehouse B will go to county B
The cost is 10 * 40 + 2 * 80 + 6 * 50 = 860 yuan