A, B two cars, a from a to B, B from B to a, at the same time, the two cars meet 1.5 hours later, after meeting, a car still need 2 hours to arrive at B, B car also need 9 / 8 hours to arrive at a, if a, B two places apart 210 km, try to find a, B two car speed

A, B two cars, a from a to B, B from B to a, at the same time, the two cars meet 1.5 hours later, after meeting, a car still need 2 hours to arrive at B, B car also need 9 / 8 hours to arrive at a, if a, B two places apart 210 km, try to find a, B two car speed

Let a and B be x and Y respectively
{1.5（x+y）=210 (2)
{9/8x+2y=210 (1)
Simplify 3x + 3Y = 420 9x + 16y = 1680 (3)
(2) (3) 7Y = 420
y=60
Then x = 80

A and B trains leave from the two places at the same time and meet in 3.6 hours. At this time, car a travels 18 kilometers more than car B. It is known that car B travels 60 kilometers per hour, and how many kilometers does car a travel per hour?

(60 × 3.6 + 18) △ 3.6 = (216 + 18) △ 3.6 = 234 △ 3.6 = 65 km) a: car a travels 65 km per hour

The distance between a and B is 80 km from a when they first meet, and the distance between a and B is 80 km after they meet
A and B two cars respectively from AB two places at the same time, the first meeting 80km away from a, after meeting two cars continue to drive, respectively to Ba immediately return, and the second meeting 40km away from B?

A and B two cars respectively from AB two places at the same time, the first meeting 80km away from a, after meeting two cars continue to drive, respectively to Ba immediately return, and the second meeting 40km away from B?
AB distance between two places:
80*3-40=200km .

Two cars a and B start from a and B at the same time and travel in opposite directions. The two cars meet in five hours
Two cars B start from a and B at the same time and travel in opposite directions. Five hours later, the two cars meet. After meeting, the two cars continue to move forward. After four hours, car a arrives at B. at this time, car B is 90 kilometers away from A. how many kilometers is the distance between a and B

a/5=(a-90)/4 4a=5(a-90) 4a=5a-450 a=450