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The length of the railway between city a and city B is 435 km. The two passenger and freight cars start from the two cities at the same time and travel in opposite directions. The passenger cars travel 60 km per hour, and the freight cars 45 km per hour. How many hours later is the distance between the two cars 15 km
Set X hours
(60+45)x=435-15
105x=420
x=4
The railway between a and B is 396km long. A train and a passenger train start from a and B at the same time and run in opposite directions. The passenger train runs 110km per hour and the freight train runs 110km per hour
It's 40 km slower than the bus. How many hours do the two cars meet?
Truck 110-40 km / h = 70 km
So it takes 396 (110 + 70) = 2.2 hours
There are 150 watermelons in the two cars. Car a is putting 40 watermelons. Car B goes to get 20 watermelons. At the same time, B has 10 more than A. how many watermelons did A. B have?
Let a be x and B be (150-x)
[(150-x)-20]-(x+40)=10
150-x-20-x-40=10
-2x+80=0
x=40
150-40=110
There are 40 in car a and 110 in car B
Party A and Party B have 150 cars in total, and Party B gives party a 20 cars. Party A is just twice as much as Party B. Party A and Party B
Lie equation
There are x vehicles in a and 150-x vehicles in B
150-x-20=2x+20
110=3x
x=36.666666666
What the hell?
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