A pile of goods, the first day of the total number of 15, the second day than the first day of 15 tons, there are still 45 tons of goods not shipped, how many tons of this pile of goods?

Let X - (15x + 15x + 15) = 45 & nbsp; & nbsp; X - (25X + 15) = 45 & nbsp; & nbsp; & nbsp; & nbsp; x-25x-15 + 15 = 45 + 15 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 35x △ 35 = 60 △ 35 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 100 a: there are 100 tons in total

There is a batch of goods in the mall. One third of them were transported on the first day, and more than 40% of them were transported on the second day. This is the remaining 20 tons. There are a total of 20 tons in this batch of goods
How much? (not equations, but arithmetic, by the way)

If only 40% is transported the next day, there will be 20 + 4 = 24 tons left
The remaining total: 1-1 / 3-40% = 4 / 15
This batch of goods is: 24 / 15 = 90 tons
Hope to help you!
If you don't understand, please ask. I wish you progress in your study!

There is a batch of goods, 20% of the total amount was transported on the first day, and 4 tons more than 1 / 4 of the total amount was transported on the second day. At this time, there are still 20 tons left. How many tons are there in this batch of goods?

43.6 tons
There are altogether x tons of goods
X-20%X-（X/4+4)=20
X=43.6

There is a batch of goods in the warehouse. 20 tons were transported in the first day, and 617 tons more were transported in the second day than in the first day. At this time, 917 tons of the total amount of this batch of goods were left to be transported. How many tons of this batch of goods are there?

[20 + 20 × (1 + 617)] / (1-917), = [20 + 20 × 2317] / (817, = 80017 × 178, = 100 (tons); a: there are 100 tons of this batch of goods

Number reasoning 11 17 23 32 ()
I just want to know how he worked it out

23 and 32 are symmetrical, 11 itself is symmetrical, then 17 and 71 are symmetrical

1 2 6 () number reasoning? There should be ideas
A、21
B、22
C、23
D、24

The order is 1 2 3 4 times D

Number reasoning 1, - 2,7, - 20, ()

1,-2,7,-20,(61)
It can be reduced to 1 - (3 * 1-1), - [3 * (- 2) - 1], - (3 * 7-1), - [3 * (- 20) - 1]
That is, the next number is negative (multiply the previous number by 3 minus 1)

What are the rules of number reasoning 2,3,5,7,11,13,20,21?
Number reasoning 2,3,5,7,11, (13), 20,21

This is a mixed sequence
The odd digit number is 251120, and their interval is 369
Even digits are 3 7 13 21, and their interval is 4 6 8

Number reasoning: - 1,4,11,21,38, ()
What do you choose in brackets?

71.
Because the difference is 5, 7, 10, 17,
Two, three, seven more
Another one, four
It's the square of one and the square of two
The square of three is nine
So 1, 4, 9
2, 3, 7, 16
Push 5, 7, 10, 17, 33
Push again - 1,4,11,21,38,71

Number reasoning: (4,6,2), (5,10,2), (8,28,2), (7,5) how can a, 21 B, 24 C, 28 d, 42 be solved?
If you do this, it means that the middle number is multiplied by twice, which has nothing to do with the third number. Although the answer has been put together, the method must be wrong
The first several formulas are correct, but if the last one is related to the third number, it should be multiplied by five instead of two. If it is double, it will not be related to the third number

None of them are accurate. This question is a
Estimation is a problem of Tianzi No.1, which investigates the combination sequence
C（4,2）=4*3/2=6
C（5,2）=5*4/2=10
C（8,2）=8*7/2=28
C（7,5）=C(7,2)=7*6/2=21

A pile of goods, the first day of the total number of 15, the second day than the first day of 15 tons, there are still 45 tons of goods not shipped, how many tons of this pile of goods?