There is a batch of goods in the warehouse, and the weight ratio of transported goods to the rest is 25%. If 64 tons are transported away, and the weight ratio of transported goods to the rest is 3:7, how many tons are there in the warehouse?

There is a batch of goods in the warehouse, and the weight ratio of transported goods to the rest is 25%. If 64 tons are transported away, and the weight ratio of transported goods to the rest is 3:7, how many tons are there in the warehouse?


25%, i.e. 1 / 4, that is to say, if the previous one is transported and the remaining one is 1:4, and 64 tons is transported, then it can be 3:7. If the original weight is set as X tons, then the remaining weight is 4x tons, and then 64 tons is transported, then the formula is (x + 64) / (4x-64) = 3 / 7, then x = 128 tons, because if the original weight is set as X tons, then



The original batch of chemical fertilizer in the warehouse was taken out 45 tons in the first time, and the second time was 2 / 5 more than the first time. The chemical fertilizer taken out twice was just 15% of the total amount. The warehouse had chemical fertilizer


The second 45 + 45x2 / 5 = 63
(45 + 63) △ 15% = 720 tons
A total of 720 tons



There are 30 tons of chemical fertilizer in the warehouse, one fifth of the total amount is taken out in the first time, the remaining one third is taken out in the second time, and () tons is taken out in the second time
The second time you take out the remaining one-third, you take out one-third of ()


If 30 × 1 / 5 = 6 tons, take out 6 tons for the first time
(30-6) × 1 / 3 = 8 tons
A: the second time we took out (8) tons, we took out 1 / 3 of (24 tons)



The first batch of chemical fertilizer transported 3 / 8 of it, the second 40%, and 45.6 tons in total. How many tons of this batch of chemical fertilizer?


Will the second 40% be the remaining 40% or the total 40%?
If the rest:
Suppose there are x tons in total, then:
3/8x+40%(x-3/8x)=45.6
5/8x=45.6
x=72.96
If all:
3/8+40%=0.775
45.6/0.725=1824/31



There is an equilateral triangle shaped land that is 180 meters long. Starting from one of its vertices, plant a tree every 10 meters. How many trees are planted on three sides?


18 trees
Divide 180 by 10 = 18



There is a triangle land with three sides of 120 meters, 150 meters and 80 meters. A tree is planted every 10 meters. How many trees are planted on the three sides? (there are trees on the three vertices.)


Analysis: every corner of the triangle needs to plant trees, so this problem can be considered as a circle: then plant trees = interval number; find the perimeter of the land, then the problem can be solved
(120+150+80)÷10,
=350÷10,
=35 (trees),
A: there are 35 trees planted on the three sides
So the answer is: 35



A triangle flower bed, one side 120 meters long, one 150 meters long, one 80 meters long, every 10 meters to plant a tree, how many trees to plant?


(120 + 150 + 80) / 10 = 35 (trees)



There is a triangle land with three sides of 120m, 160m and 80m respectively. Plant a tree every 20m, and plant a tree at each of the three vertices
How many trees are planted?


(120+80+160)/20-1
=360/20
=18



Fill 10, 15, 20, 30, 40 and 60 in the circle below to make the product of three numbers on each side of the triangle equal


The picture is as follows: (the answer is not unique)



Fill the six numbers 1, 2, 3, 4, 8 and 12 in the circle on the right to make the product of the three numbers on each line equal


According to the analysis, the answers are as follows: