Find the rule of 9,1,4,3,40 and fill in the next number If the answer is 121, what is the law
Divide each one by three and see the remainder
The remainder is 0;
The remainder is 1;
The remainder is 1;
The remainder is 0;
The remainder is 1;
If there are two numbers with the remainder of 1, then there is a multiple before subtracting 1, that is, n = (4-1) △ 1 = 3; then there is (x-1) △ 40 = 3 (x is the sixth number)
That is: x = 40 × 3 + 1 = 121
What is the number after 9.1.4.3.40
a1=9,
a2=1,
a3=4,
a4=3,
a5=40,
a6=?.
a5=(a1+a2)*a3*a4/3=(9+1)*4*3/3=40
a6=(a2+a3)*a4*a5/3=(1+4)*3*40/3=120
a6=120
9,1,4,3,40,(121
(9 * 1 + 4) + (3 * 40) = 14 + 120 = 314 A: possible