There are 28 workers in the woodworking factory. Two workers can process three tables a day, and three workers can process 10 chairs a day. Now how to arrange the labor force so that one table can be matched with four chairs?
Let x workers process tables and Y workers process chairs. According to the meaning of the question, we get x + y = 284 × 32x = 103y, sort out: x + y = 28x = 59y, and solve: x = 10Y = 18. Answer: only 10 workers process tables and 18 workers process chairs, can we make one table and four chairs match
There are 28 people in a woodworking factory. Two workers can process three tables a day, and three workers can process 10 chairs a day (one variable linear equation, two-step solution)
Now how to arrange the labor force is to produce a table with chairs. (one table with four chairs)? Chairs. (one table with four chairs)?
Set up x workers to process the table, then 28-x workers to process the chair
3x/2*4=10(28-x)/3
The solution is x = 10
28-10=18
Answer: arrange 10 workers to process tables and 18 chairs
There are 28 people in a woodworking factory. Each worker can process 3 tables or 16 chairs a day
How to arrange the labor force to make the table and chair match. (one table and four chairs match)
X+Y=28
3X/16Y=1/4
X=28-Y
16Y=12X
16Y=12*(28-Y)
Y=12
X=16