There are 28 workers in the woodworking factory. Two workers can process three tables a day, and three workers can process 10 chairs a day. Now how to arrange the labor force so that one table can be matched with four chairs?

There are 28 workers in the woodworking factory. Two workers can process three tables a day, and three workers can process 10 chairs a day. Now how to arrange the labor force so that one table can be matched with four chairs?

Let x workers process tables and Y workers process chairs. According to the meaning of the question, we get x + y = 284 × 32x = 103y, sort out: x + y = 28x = 59y, and solve: x = 10Y = 18. Answer: only 10 workers process tables and 18 workers process chairs, can we make one table and four chairs match

There are 28 people in a woodworking factory. Two workers can process three tables a day, and three workers can process 10 chairs a day (one variable linear equation, two-step solution)
Now how to arrange the labor force is to produce a table with chairs. (one table with four chairs)? Chairs. (one table with four chairs)?

Set up x workers to process the table, then 28-x workers to process the chair
3x/2*4=10(28-x)/3
The solution is x = 10
28-10=18
Answer: arrange 10 workers to process tables and 18 chairs

There are 28 people in a woodworking factory. Each worker can process 3 tables or 16 chairs a day
How to arrange the labor force to make the table and chair match. (one table and four chairs match)

X+Y=28
3X/16Y=1/4
X=28-Y
16Y=12X
16Y=12*(28-Y)
Y=12
X=16