Divide the nine numbers 39, 45, 56, 60, 70, 78, 84, 91 into three groups to make the scores of the three numbers in each group equal

Divide the nine numbers 39, 45, 56, 60, 70, 78, 84, 91 into three groups to make the scores of the three numbers in each group equal

There are only eight numbers. How can I help you?

The nine numbers 39, 45, 49, 56, 60, 70, 78, 84 and 91 are divided into three groups so that the products of the three numbers in each group are equal

First, decompose each number
39 45 49 56 60 70 78 84 91
(3*13)(3*3*5)(7*7)(2*2*2*7)(2*2*3*5)(2*5*7)(2*3*13)(2*2*3*7)(7*13)
As you can see, there are 9 2, 6 3, 3 5, 6 7 and 3 13 in total. It's easy to do next. They can be divided into three groups, so that each group has 3 2, 2 3, 1 5, 2 7 and 1 13
Group 1: (2 * 2 * 2 * 7) (7 * 13) (3 * 3 * 5)
Group 2: (2 * 2 * 3 * 5) (2 * 3 * 13) (7 * 7)
Group 3: (2 * 2 * 3 * 7) (2 * 5 * 7) (3 * 13)
All factors of each group are identical, so the product is the same
Group 1: 56 91 45
Group 2: 60 78 49
Group 3: 84 70 39

Fill in 0.19 0.28 0.37 () 0.64 () 0.55 according to the rule

Fill in 0.19 0.28 0.37 (0.46) 0.550.64 according to the rule