The sum of the first four terms of an arithmetic sequence is 24, and the difference between the sum of the first five terms and the sum of the first two terms is 27

Let the first item be A1 and the tolerance be P
a1+a2+a3+a4=24
a1+a2+a3+a4+a5-（a1+a2）=a3+a4+a5=27
Because it is an arithmetic sequence, so A3 + A4 + A5 = 3A4, so A4 = 9
And a1 + A4 = A2 + a3 = 24 / 2 = 12
So A1 = 12-9 = 3
So the tolerance P = (9-3) / (4-1) = 2
So the general formula of this arithmetic sequence is an = 2 (n-1) + 3 = 2n + 1

The sum of the first four terms of an arithmetic sequence is 24, and the difference between the sum of the first five terms and the sum of the first two terms is 27

Ls, if you want to calculate S100, you also list it all?
S4=24
S5-S2=27
therefore
4a1+0.5*4*(4-1)*d=24
[5a1+0.5*5*(5-1)*d]-(2a1+d)=27
The solution is as follows
a1=3
d=2
So an = 3 + 2 * (n-1) = 2n + 1

The sum of the first four terms of an arithmetic sequence is 24, and the difference between the sum of the first five terms and the sum of the first two terms is 27?
Find the set M = {M / M = 2N-1, n belongs to n *, and M = {M / M = 2N-1

S5-S2=a3+a4+a5
=3a4
That is: 3A4 = 27 get: A4 = 9
S4=4(a1+a4)/2=2(a1+a4)
That is: 2 (a1 + 9) = = 24
The solution is: A1 = 3
A4 = a1 + 3D, so d = (a4-a1) / 3 = 2
an=a1+(n-1)d
=3+2(n-1)
=2n+1

The sum of the first four terms of an arithmetic sequence is 24, and the difference between the sum of the first five terms and the sum of the first two terms is 27