2√2(√2+1/√2)-(√27-√12/√3)

2√2(√2+1/√2)-(√27-√12/√3)


Original formula = 2 * 2 + 2 - √ (27 / 3) + √ (12 / 3)
=6+2-3+2
=7



[√27+√(1/3)]-[√12-√(1/5)+√45]


[√27+√(1/3)]-[√12-√(1/5)+√45]
=[3√3+√3/3]-[2√3-√5/5+3√5]
=3√3+√3/3-2√3+√5/5-3√5
=√3+√3/3+√5/5-3√5
=4√3/3-14√5/5



2√12+3√48+√27
2 root 12 + 3 root 48 + root 27


A:
2√12+3√48+√27
=2√(4*3)+3√(16*3)+√(9*3)
=2√4*√3+3√16*√3+√9*√3
=2*2√3+3*4*√3+3*√3
=4√3+12√3+3√3
=19√3