There is a column of numbers: 1 / 1, 3 / 1, 5 / 2, 7 / 3, 9 / 5, 11 / 8. What is the seventh number

There is a column of numbers: 1 / 1, 3 / 1, 5 / 2, 7 / 3, 9 / 5, 11 / 8. What is the seventh number

It can be found that the numbers on the left side of the fractional line are 1, 3, 5, 7, 9, 11, and the rule is 1 + 2 = 3, 3 + 2 = 5, and 9 + 2 = 11
The numbers on the right side of the fractional line are 1, 1, 2, 3, 5, 8. The rule is 1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8
So the seventh number is 11 + 2 = 13 on the left and 5 + 8 = 13 on the right
So the seventh number is 13 / 13

From a column of numbers 1, 5, 9 In 93 and 97, take any 14 numbers, and prove that the sum of two numbers must be equal to 102

The general term of this column is 4n-3 (n = 1,2,3... 25)
It was found that 5 + 97 = 9 + 93 = 13 + 89 =. = 49 + 53 = 102, a total of 12 pairs
As long as one of the 12 pairs appears at the same time, the sum of the two numbers will be equal to 102
If no pair appears at the same time, then each pair can only take one, taking 12 numbers
Because there is no number and 1 can add up to 102, so 1 can take 13 numbers
But take one more pair, then one of the above 12 pairs will appear at the same time, that is, the sum of two numbers must be equal to 102

Sequence 1 8 9 4 () 1 / 6

A1 = 1 * 4 (where it means the fourth power of 1) = 1, A2 = 2 * 3 = 8, A3 = 3 * 2 = 9, A4 = 4 * 1 = 4, A6 = 6 * (- 1) = 1 / 6
So A5 = 5 * 0 = 1, an = a * (5-N)