Known sequence 1 1 2 3 5 8 13 Find the remainder of the number 2010 △ 11

Known sequence 1 1 2 3 5 8 13 Find the remainder of the number 2010 △ 11

The remainder of the number 2010 △ 11 is 0
Sequence, corresponding remainder:
1 : 1
1 : 1
2 : 2
3 : 3
5 : 5
8 : 8
13 : 2
21 : 10
34 : 1
55 : 0
89 : 1
144 : 1
233 : 2
377 : 3
610 : 5
987 : 8
As mentioned above, it is easy to know that there is a rule for the remainder of 11, one cycle for every 10 numbers
2010/10 =201 …… 0
Therefore, the remainder of the number 2010 △ 11 is equivalent to the remainder of the number 10 55, which is 0

The remainder of a three digit number divided by 5 may be () and the largest remainder is () formula

The remainder of a three digit number divided by 5 may be (0, 1, 2, 3, 4) and the maximum remainder is (4)
Because the remainder is less than the divisor, now the divisor is 5, so the remainder is less than 5
120÷5=24
121÷5=24…… one
122÷5=24…… two
123÷5=24…… three
124÷5=24…… four

A number divided by 4, the remainder is 3, the number of three times divided by 4, what is the remainder? To calculate the formula

(4N + 3) * 3 = 12n + 9 / 4 = 3N + 2 remainder 1