There are a total of 2012 balls in the three piles. If Gao takes the same number of balls from each pile, there are still 17 balls left in the second pile, and the number of balls left in the first pile is twice that of the third pile, then the third pile is the original pile______ A small ball

There are a total of 2012 balls in the three piles. If Gao takes the same number of balls from each pile, there are still 17 balls left in the second pile, and the number of balls left in the first pile is twice that of the third pile, then the third pile is the original pile______ A small ball


In the third pile, there are only y ones left in the third pile, and then: x + 2Y + (x + 17) + (x + 17) + (x + 17) + (x + y) will be: x + 2Y + (x + 2Y + (x + 17) + (x + 17) + (x + 17) + (x + 17) + (x + y) + (x + y) will be: x + 2Y + (x + 2Y + (x + 17) + (x + 17) + (x + y) + (x + y) + (x + y) will be (x + y) in the third pile, then: then: x + 2x + 2Y will be: x + 2x + 2Y, then: x + 2x + 2x + 2Y (x + X + X + 2Y) is: x + 2x + 2x + 2x + 2X + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2Y (x + 2x + 2x + 2x + 2nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; &A: there are 665 balls in the third pile. So the answer is: 665 balls



There are 160 pieces in three piles. The second pile is three times of the first pile, and the third pile is 20 more than two times of the second pile. How many more pieces in the third pile than the first pile?


If the first stack is set to x, it will be x 3x 6x + 20 respectively
Total: 10x + 20 = 160 x = 14
5X+20=90
A: 90 more



1-2+3-4+5-6+7-8+9-10+11-12+13-14+15-16+17...+2011-2012


The sum of every two items is - 1, there are 2012 items in total, so there are 1006 - 1, so the answer is - 1006



In rational numbers 1.7, - 17,0, negative 5 and 2 / 7, - 0.001, - 2 / 92012 and negative 1, how many are integers, negative numbers and fractions?


4 5 4



There are 12 red, yellow and blue glass balls in the box. At least a few of them can be taken out to ensure that the three colors of the glass balls are available


Think: to ensure that take out three different colors of the ball, then consider from the worst direction: if you take 12, are the same color how to do? So, you have to take 12 first, to ensure that take out one color; then, take 12, the second color was taken out. Now, only one color, then, no matter how many you take



There are two red, black and white glass balls in an opaque box. To ensure that there are three colors of glass balls, how many do he take out at least?
It's three colors, all the formulas


I don't know if there are any other conditions for the title. If that's the case, five of the three kinds of "guarantee" need to be taken. In fact, it's an enumerative solution. It's obviously impossible to take one or two. In addition to red, white and black, there may be red, white, black and white, black and white, etc. in the case of three. In the case of four kinds of "guarantee", there may be red, white, black, black and red, which is not enough



There are eight red, yellow and blue glass balls in one box. At least a few glass balls can be found in this box at a time,
Make sure there are two pairs of glass balls of the same color?


Make sure there are two pairs of 10



There are six red, yellow and blue balls in one pocket. At least () balls in three different colors should be found


6+6+1=13



A bag of red, orange, yellow three colors of the ball, each arbitrary touch 2, then at least a few people to ensure that there are two or more people choose the same ball


6 + 1 = 7 (people); answer: at least 7 people can guarantee that two or more people choose the same ball



There are two kinds of balls of the same size and different colors in the bag. If you touch at least a few balls, you can ensure that there are two balls of the same color


There are (how many) two balls of the same size and different colors in the bag. At least a few balls can be found out to ensure that there are two balls of the same color