In the Pentagon ABCDE, AE is parallel to CD, angle a is equal to 107 degrees, angle B is equal to 121 degrees, find the degree of angle C

The inner angle sum formula of polygon: (n-2) * 180 degree
So the sum of the internal angles of a Pentagon is 540 degrees
Because AE is parallel to CD, ∠ d = ∠ e = 90 degree
Then ∠ C = 540 ° - 107 ° - 121 ° - 2 * 90 ° = 132 °
(Note: the pentagonal ABCDE letters are shown in sequence)

In the pentagonal ABCDE, AE is parallel to CD, angle a = 113 ° and angle B = 119 ° to find the degree of angle C

It should be AE / / CD, so the angle e + D = 180 degrees
The sum of internal angles of Pentagon is (5-2) * 180 ° = 540 °
Angle c = 540 - angle a - angle B - angle e - angle d = 540 ° - 113 ° - 119 ° - 180 ° = 128 °

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