The swimming pool of a school gymnasium is 50 meters long, 20 meters wide and 1.2 meters deep. How many tiles are needed to paste 0.16 square meters of tiles on the wall and bottom of the pool?

Bottom area = 50 * 20 = 1000 square meters
Side area = 2 * (50 + 20) * 1.2 = 168 square meters
Total area = 1000 + 168 = 1168 square meters
Number of bricks = 1168 / 0.16 = 7300

Put a 50 meters long, 20 meters wide, 2 meters deep swimming pool tile, if you use the area is 4 square decimeters of tile paste, at least how many pieces of this

First calculate the flat area of the swimming pool: = 50x20 + 50x2x2 + 20x2x2 = 1280 square meters, the area of ceramic tiles is 4 square decimeters = 0.04 square meters, the number of ceramic tiles = 1280 △ 0.04 = 32000, so at least 32000 ceramic tiles are needed

A cuboid shaped children's swimming pool is 40 meters long, 14 meters wide and 1.2 meters deep. Now, how many square tiles with an area of 16 square decimeters need to be pasted on the four walls and the bottom of the pool?

40 × 14 + 40 × 1.2 × 2 + 14 × 1.2 × 2, = 560 + 96 + 33.6, = 689.6 (square meters), 689.6 square meters = 68960 square decimeters, 68960 △ 16 = 4310 (pieces); answer: 4310 pieces are needed

A cuboid swimming pool, 55 meters long, 30 meters wide, 2 meters deep, in the four walls and pool bottom paste a layer of tiles, paste tile area is how many square meters?
Please,

55×30+（55×2+30×2）×2
=1650+340
=1990 square meters

The swimming pool of a school gymnasium is 50 meters long, 20 meters wide and 1.2 meters deep. How many tiles are needed to paste 0.16 square meters of tiles on the wall and bottom of the pool?