A cuboid swimming pool is 20 meters long, 15 meters wide and 2 meters deep. Now we need to put cement on each side of the swimming pool, and then paste ceramic tiles with a length of 4 decimeters. How many such tiles are needed? If 5 kg of cement is used per square meter, how much cement will be used?

A cuboid swimming pool is 20 meters long, 15 meters wide and 2 meters deep. Now we need to put cement on each side of the swimming pool, and then paste ceramic tiles with a length of 4 decimeters. How many such tiles are needed? If 5 kg of cement is used per square meter, how much cement will be used?


4 decimeter = 0.4 meter, 20 × 15 + (20 × 2 + 15 × 2) × 2, = 300 + 140, = 440 (square meter), 440 ^ (0.4 × 0.4), = 440 × 0.16, = 2750 (piece); 440 × 5 = 2200 (kg); answer: if you need 2750 tiles like this, you need 2200 kg of cement



There is a rectangular sheet of iron, 96 cm long and 80 cm wide. Cut it into a rectangle of the same size. There is no left. What is the longest side length of this rectangle


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The longest side length is the greatest common factor of 96 and 80: (96,80) = 16 (CM)



Cut a rectangular sheet of iron 80 cm in length and 60 cm in width into a square. What is the longest side length of the sheet of iron? At least how many sheets can be cut?
I'm sorry~


The greatest common divisor of 60 and 80 is 20, so the longest side of iron sheet is 20 cm, which can cut 12 pieces



A rectangular sheet of iron, 96 cm long and 80 cm wide, should be cut into a square of the same size without any surplus. What is the longest side length of this square? How many pieces are they cut into?


80 = 2 × 2 × 2 × 5, 96 = 2 × 2 × 2 × 2 × 3, the greatest common factor of 80 and 96 is: 2 × 2 × 2 = 16; (96 / 16) × (80 / 16), = 6 × 5, = 30 (blocks); answer: the longest side length of this square is 16 cm, which is cut into 30 blocks