Cut two small squares with side length of 2 into a large square. The side length x of the large orthomorphic is an irrational number. Can you estimate the approximate value of X with two decimal places How about three decimal places?

Cut two small squares with side length of 2 into a large square. The side length x of the large orthomorphic is an irrational number. Can you estimate the approximate value of X with two decimal places How about three decimal places?

The side length of a large orthomorphic x = √ 8 = 282847
Keep two decimal places ≈ 2,83
Keep three decimal places ≈ 2828

Is the length of AE, be rational number and the area of △ Abe rational number in rectangular ABCD with ∠ DAE = ∠ CBE = 45 ° and ad = 1?

It is known from the title that in the right triangle ade and BCE, ∠ DEA = ∠ CEB = 90 ° - 45 ° = 45 ° so the triangle ade and BCE are isosceles right triangles, then de = CE = ad = 1, AE = EB = 2 under the root sign, and ∠ AEB = 180 ° - DEA - ∠ CEB = 90 ° so the triangle Abe is right triangle, and ab = de + CE = 2, then the area s

As shown in the figure, it is a square with one side. The number represented by the length of three dashed lines in the figure is rational
Irrational number

In other words, we just did this problem yesterday. All three of them are irrational numbers. Well, they are based on the Pythagorean theorem. The Pythagorean theorem is that the square of two right angles equals the square of the hypotenuse, and then all three of them are irrational numbers

In quadrilateral ABCD, ad ∥ BC, AB are not parallel DC, M is the midpoint of AD, MB = MC

∠AMB=∠MBC=∠MCB=∠DMC,
BM=CM
AM=DM
Triangle ABM congruent triangle DCM
AB=DC
Get proof