As shown in the figure, the area ratio of triangle ABC to triangle ade is 3:4, and the area of triangle ABF is 10 square centimeter larger than that of triangle FCE

As shown in the figure, the area ratio of triangle ABC to triangle ade is 3:4, and the area of triangle ABF is 10 square centimeter larger than that of triangle FCE

Because the area ratio of triangle ABC to triangle ade is 3:4, so AB: de = 3:4, then AB: CE = 3:1, because triangle ABF is similar to triangle FCE, and the similarity ratio is 3:1, then their area ratio is 9:1, 9 + 1 = 10, so the sum of triangle ABF and triangle FCE area is: 10 △ 810 = 12

As shown in the figure, the area ratio of triangle ABC to triangle ade is 3:4, and the area of triangle ABF is 10 square centimeter larger than that of triangle FCE

Because the area ratio of triangle ABC to triangle ade is 3:4, so AB: de = 3:4, then AB: CE = 3:1, because triangle ABF is similar to triangle FCE, and the similarity ratio is 3:1, then their area ratio is 9:1, 9 + 1 = 10, so the sum of triangle ABF and triangle FCE area is: 10 △ 810 = 12

ABCD is a rectangle. The area of triangle ade is less than 15 square centimeters. What is the area of triangle ABF?

Where is the f point? Is the e point inside or outside the rectangle? Is it on the same plane as the rectangle?
The title is not clear and cannot be calculated. Please complete the title

Given the square ABCD, the straight line passing through C intersects the extension lines of AD and ab at points E and f respectively, and AE = 15 and AF = 10, the side length of square ABCD is calculated

∵ BC ∥ AE ∥ FBC ∥ FAE ∥ bcae = fbfA if the side length of a square is x, then x15 = 10 − X10 ∥ x = 6