As shown in the figure, the quadrilateral ABCD is a rectangle, ∠ EDC = ∠ cab, ∠ Dec = 90 ° (1) prove: AC ‖ de; (2) make BF ⊥ AC at point F through point B, connect EF, try to distinguish the shape of quadrilateral BCEF, and explain the reason

As shown in the figure, the quadrilateral ABCD is a rectangle, ∠ EDC = ∠ cab, ∠ Dec = 90 ° (1) prove: AC ‖ de; (2) make BF ⊥ AC at point F through point B, connect EF, try to distinguish the shape of quadrilateral BCEF, and explain the reason


(1) It is proved that the ∵ quadrilateral ABCD is a rectangle, ∵ ab ∥ CD, ∵ ACD = ∵ cab, ∵ EDC = ∵ cab, ∵ EDC = ∵ ACD, ∵ AC ∥ de; (2) the quadrilateral BCEF is a parallelogram. The reasons are as follows: ∵ BF ⊥ AC, quadrilateral ABCD is a rectangle,