As shown in the figure, in square ABCD, take BC as the edge, make equilateral triangle BCE outside the square, connect De, then the degree of angle CFE is degree

As shown in the figure, in square ABCD, take BC as the edge, make equilateral triangle BCE outside the square, connect De, then the degree of angle CFE is degree

It is to find the degree of CDE
In square ABCD, BC = CD, ∠ BCD = 90 °
In equilateral triangle BCE, BC = CE, ∠ BCE = 60 °
∴CD=CE,∠DCE=90°+60°=150°
∠CDE=∠CED = (180° - 150°) /2 = 15°

As shown in the figure, e is a point in the square ABCD. If △ Abe is an equilateral triangle, then ∠ DCE=______ Degree

∵ quadrilateral ABCD is a square, ∵ AB = BC, ∵ △ Abe is an equilateral triangle, ∵ △ Abe is an equilateral triangle, ∵ AE = AB = be, ∵ Abe = 60 °, ∵ EBC = 90-60 ° = 30 °, BC = be, ∵ ECB = ∵ BEC = 12 (180-30 °) = 75 °, ∵ DCE = 90-75 ° = 15 °. So the answer is 15

As shown in the figure, e is a point in the square ABCD. If △ Abe is an equilateral triangle, then ∠ DCE=______ Degree

∵ quadrilateral ABCD is a square, ∵ AB = BC, ∵ △ Abe is an equilateral triangle, ∵ △ Abe is an equilateral triangle, ∵ AE = AB = be, ∵ Abe = 60 °, ∵ EBC = 90-60 ° = 30 °, BC = be, ∵ ECB = ∵ BEC = 12 (180-30 °) = 75 °, ∵ DCE = 90-75 ° = 15 °. So the answer is 15

In square ABCD, there is a point E, Abe is an equilateral triangle, connecting CE and De, how many degrees is the angle DCE?
A............D
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:E.:
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B............C

If Abe is an equilateral triangle, the angle AEB is equal to 60
ABC = 90 and ECB = 30
AC = AE, BCE = 75
Angle BCD = 90
Angle DCE = 90-75 = 15