It is known that ABCD and abef are two squares and not in the same plane, m and N are the points on the diagonal AC and FB respectively, and am = FN

It is known that ABCD and abef are two squares and not in the same plane, m and N are the points on the diagonal AC and FB respectively, and am = FN

It is known that ABCD and abef are two squares and not in the same plane, m and N are the points on the diagonal AC and FB respectively, and am = FN

Given that the quadrilateral ABCD and BaFe are two congruent squares, point m is on AC, point n is on FB, am = FN, the BCE of Mn ‖ plane is proved

If MP & nbsp; / / & nbsp; ad is made through M and ab is connected to P, then because square ABCD and square abef are congruent, AC = BF, am = FN, MC = Nb, & nbsp; so PN & nbsp; / / & nbsp; AF, & nbsp; so PN & nbsp; / / & nbsp; be, PM plane BCE, bc plane BCE, PM & nbsp

It is known that ABCD and abcf are two squares and not in one plane, m and N are the points on diagonal AC and FB respectively, and am = FN. Verification: Mn / / plane CBE
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If we know ABCD, abcf is two squares, and if we make a mistake, abcf is two squares. If we know ABCD, abef is two squares, as shown in the figure, let P ∈ AB & nbsp; & nbsp; make AP: Pb