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Increase one side of a square by 2cm and shorten the other side by 20% to get a rectangle, which is equal to the area of the original square. Then the area of the square is (), and the perimeter of the rectangle is () Be specific about the formula and meaning
Let the side length of the square be a, then the length and width of the rectangle are: (a + 2), (0.8A)
According to the equal area of square and rectangle: a * a = 0.8A * (a + 2)
So a = 8
So square area = a * a = 64 square centimeters
Rectangle circumference = (1.8A + 2) * 2 = (1.8 * 8 + 2) * 2 = 32.8 cm
There are two rectangles in size. The difference in their area is 95 square centimeters. How many square centimeters are the two squares in size
The width of the small rectangle is 5 cm
Let the length of two squares be a, B (a > b). If the length of two squares is a positive natural number, then a & # 178; - B & # 178; = (a + b) (a-b) = 95 = 19 * 5 = 95 * 1A + B = 19a-b = 5A = 12, B = 7a & # 178; = 144, B & # 178; = 49 or a + B = 95a-b = 1A = 48, B = 47a & # 178; = 2304, B & # 178; = 2209
The sum of the areas of the two squares is 65 square centimeters, and the side length ratio is 2:3. What are the areas of the two squares?
The area ratio is the square of the side length ratio,
So the two areas are 65 * 4 / (4 + 9) = 20 square centimeters
65 * 9 / (4 + 9) = 45 square centimeter
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- 15. The area of a rectangle is X & # 178; - Y & # 178;, and the area of a square with its long side as its side length is The area of a rectangle is X & # 178; - Y & # 178;, and the area of a square with its long side as its side length is I know the solution is as follows: X & # 178; - Y & # 178; = (x + y) (X-Y). When x > 0, Y > 0, the long side is x + y, so the area is (x + y) &# 178; = x & # 178; + 2XY + Y & # 178; But when x ＞ 0, y ＜ 0, the long side is (X-Y), so the area is (X-Y) &# 178; = x & # 178; - 2XY + Y & # 178; But this is a single choice question, and the answer is X & # 178; + 2XY + Y & # 178; what's wrong with the second idea?
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