The side length of square a is 8 cm. The side length of square a of square B is five times that of square A. how much more area is square B than square a What's the percentage?

B side length is 10 cm
A surface area 6 * 8 * 8
B surface area 6 * 10 * 10
A few more (6 * 10 * 10-6 * 8 * 8) / (6 * 8 * 8) = 9 / 16

If there is a square whose side length increases by 8 cm, the area of the square will increase by 208 square cm. What is the area of the original square?

8 * 8 = 64 square centimeter
208-64 = 144 square centimeters
144 / 2 = 72 square centimeter
72 / 8 = 9 cm
9 * 9 = 81 square centimeter

When the side length of a square increases by 8 cm, the area increases by 160 square cm. How much is the original square area?

Let the original side length be x cm
Then (x + 8) ² - X & #178; = 160
x²+16x+64-x²=160
16x=96
x=6
So the original area is X & # 178; = 36 square centimeters

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