The length of a rectangle is reduced by 3cm, and the width is increased by 2cm to get a square, and the square area is 1 square centimeter smaller than the rectangle area What are the length and width of the original rectangle?

The length of a rectangle is reduced by 3cm, and the width is increased by 2cm to get a square, and the square area is 1 square centimeter smaller than the rectangle area What are the length and width of the original rectangle?

Let the side length of a square be x, then there is
(x+3)(x-2)-1=x^2
The solution is x = 7
So the original length and width are 10 and 5 respectively

After adding 3cm to the two adjacent sides of a square, we get a new square. The area of the new square is 39 square centimeters larger than that of the original square. What's the area of the original square?

Let the side length of the original square be x cm. According to the meaning of the question, we can get: 3x + 3x + 3 × 3 = 39 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 6x + 9 = 39 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 6x = 30 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 5 the area of the original square: 5 × 5 = 25 (square centimeter) a: the area of the original square is 25 square centimeter

If the side length of a square is increased by 3cm, its area will be increased by 39cm. What is the side length?

39/3=13