Fold a 24 cm square paper in half four times to get a small square. What is the area of the small square______ Square centimeter

Fold a 24 cm square paper in half four times to get a small square. What is the area of the small square______ Square centimeter


Side length of small square: 24 × 14 = 6 (CM), area of small square: 6 × 6 = 36 (square cm); answer: the area of this small square is 36 square cm



The square of side length () has an area of (), () about 1 square centimeter


One centimeter, one square centimeter, nail plate of little finger



A square, its area is 25 square centimeters, its side length is ()
A. 4cm B. 5cm C. 6cm


Because 5 × 5 = 25, the side length of the square is 5cm



Square photo frame middle part side length a cm, photo frame width b cm, calculate the photo frame area?


(a+2b)^2-a^2



The perimeter of a rectangle is 24cm. If the length of the rectangle is reduced by 2cm and the width is increased by 3cm, it becomes a square. Find the area of the original rectangle


The length of the rectangle is reduced by 2cm, and the width is increased by 3cm
2 + 3 = 5 (CM)
The width is:
(24-5 × 2) △ 4 = 3.5 (CM)
Long as:
3.5 + 5 = 8.5 (CM)
the measure of area:
8.5 × 3.5 = 29.75 (cm2)



As shown in the figure, the length of a rectangle is reduced by 4cm and the width is increased by 2cm. The result is a square whose area is equal to that of the original rectangle. Find the length and width of the original rectangle


Let the length and width of the original rectangle be xcm and YCM respectively. According to the meaning of the title, we get x − 4 = y + 2, ① xy = (x − 4) (y + 2) ②. From ②, we get: xy = XY + 2x-4y-8, that is, x-2y = 4, x = 2Y + 4, substituting into ①, we get: 2Y + 4-4 = y + 2, solving y = 2, substituting y = 2 into ①, we get: x = 8, the solution of the equations is: x = 8y = 2, so the original rectangle is 8cm in length and 2cm in width



If the length of a rectangle is reduced by 4cm and the width is increased by 2cm, a square can be obtained, and its area is equal to that of the rectangle
Find the length and width of the rectangle, the process of solving the problem and the reasons for listing the equations. Thank you


Let x * y = (Y-2) * (x + 4) and x = y solve the system of equations x * y = (Y-2) * (x + 4) with length x + 4 and width Y-2, and get x = y = 4, that is, length 8cm and width 2cm



As shown in the figure, the length of a rectangle is reduced by 4cm and the width is increased by 2cm. The result is a square whose area is equal to that of the original rectangle. Find the length and width of the original rectangle


Let the length and width of the original rectangle be xcm and YCM respectively. According to the meaning of the title, we get x − 4 = y + 2, ① xy = (x − 4) (y + 2) ②. From ②, we get: xy = XY + 2x-4y-8, that is, x-2y = 4, x = 2Y + 4, substituting into ①, we get: 2Y + 4-4 = y + 2, solving y = 2, substituting y = 2 into ①, we get: x = 8, the solution of the equations is: x = 8y = 2, so the original rectangle is 8cm in length and 2cm in width



The perimeter of the big square is 96 cm longer than that of the small square, and their area is 960 square cm different


Let the side length of a small square be xcm, then the side length of a large square is (x + 96 △ 4) cm. (x + 96 △ 4) 2-x2 = 960.48x = 384, and the solution is x = 8, ‖ x + 96 △ 4 = 32. A: the side length of a large square is 32cm, and that of a small square is 8cm



How much less is the area of a square frame with a circumference of 72 cm pulled into a parallelogram frame with a height of 15 cm?


72 △ 4 = 18 (CM), 18 × 18-18 × 15, = 324-270, = 54 (cm 2), a: the area is reduced by 54 cm 2