What is the side length of a square with an area of 20 square centimeters? Answer with primary school knowledge

What is the side length of a square with an area of 20 square centimeters? Answer with primary school knowledge


Let the side length of a square be x cm
xx=20
According to the multiplication formula: 446, 5525. The answer should be between 4cm and 5cm



The area of a square is 640 square meters. If the side length of the square is reduced by 2 times, the square will be the same as it is now


160



As shown in the figure, the sum of the side lengths of the two squares is 20 cm, the difference between the area of the two squares is 40 cm, and the area of the small square is 20 cm______ Square centimeter


Let the side length of a large square be x cm, and the side length of a small square be y cm. From the meaning of the question, x + y = 20x2 − y2 = 40. By solving the equations, x = 11y = 9, the area of a small square is 9 × 9 = 81 (square cm). Answer: the area of a small square is 81 square cm. So the answer is: 81



The size of two squares, the side length of 20 cm, the difference between the area of 40 square centimeters, small square area


Let the length of a small square be X
(20-x)*(20-X)-X*X=40
X=9
9 * 9 = 81 square centimeter



As shown in the figure, the sum of the side lengths of the two squares is 20 cm, the difference between the area of the two squares is 40 cm, and the area of the small square is 20 cm______ Square centimeter


Let the side length of a large square be x cm, and the side length of a small square be y cm. From the meaning of the question, x + y = 20x2 − y2 = 40. By solving the equations, x = 11y = 9, the area of a small square is 9 × 9 = 81 (square cm). Answer: the area of a small square is 81 square cm. So the answer is: 81



It is known that the sum of the side lengths of two squares is 20 cm, and the difference between their areas is 40 square cm. Find the side lengths of the two squares


Let the side length of a square be x and the side length of the other square be y.x + y = 20. ① x × X-Y × y = 40. ② we get x = 20-y from ①. ③ we get (20-y) × (20-y) - y × y = 40 (20 × 20) - (20 × y) + y × Y-Y × y = 40400-40 × y = 40-40



A square has an area of 40 square meters. How long is its side?


40 under the root sign, about 6.3245 meters



A square room has an area of 40 square meters and its side length is between two adjacent integers


Suppose the side length of a square is X. then the square of X is equal to 40. So x = root 40. The square of 6 is 36, and the square of 7 is 42.36 "40" 42, so the side length is between 6 and 7



If the length and width of a square test field are increased by 5 meters, the area will be increased by 875 square meters? Draw a picture first, then answer


The following figure is as follows: the length of the original square is a, and according to the meaning of (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) - A2 = 875, and the following is (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) (a + 5) - A2 = 875, according to the meaning of (a + 5) (a + 5) (a + 5) (a + 5 + 5) - 2 = 875, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & & nbsp; & nbsp; & nbsp; & & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; &A = 850 / 10, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; a = 85.85 × 85 = 7225 (M2). A: the original area of the test field was 7225 m2



If the length and width of a square test field are increased by 5 meters, the area will be increased by 875 square meters? Draw a picture first, then answer


The drawing is as follows: let the length of the original square be a. according to the meaning of the title, we get (a + 5) (a + 5) - A2 = 875, & nbsp; & nbsp; & nbsp; A2 + 10A + 25-a2 = 875, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 10A + 25 = 875, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp