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The area of the overlapping part of two rectangles is equivalent to one sixth of the area of the large rectangle and one fourth of the area of the small rectangle. What is the ratio of the large and small rectangles
Big: small
=1÷1/6：1÷1/4
=3：2
Do not understand can ask, help please adopt, thank you!
The area of the overlapping part of the two rectangles is equivalent to 1 / 6 of the area of the large rectangle and 1 / 4 of the area of the small rectangle,
The area of the non overlapping part is 228 square centimeters, so how about the area of the overlapping part?
Let the area of the large rectangle be x and the area of the small rectangle be y
Get the equations
x/6=y/4
5x/6+3y/4=228
Solution
x=171,y=114
Overlap area = 171 / 6 = 28.5 (cm2)
As shown in the figure, two rectangles A and B are overlapped. The area of the overlapped part is 1 / 3 of a and 1 / 5 of B. It is known that the area of B is 60 square centimeters,
How many square centimeters is the area of a? (solve the equation)
What about the picture?
As shown in the figure, two parallelograms A and B are overlapped. The area of the overlapped part is 14 of a and 16 of B. It is known that the area of a is 12 square centimeters. Then the area of B is more than that of A______ Square centimeter
The area of B is a: (1 △ 16) / (1 △ 14), = 6 △ 4, = 1.5 (Times); the area of B is more than that of a: 12 × (1.5-1), = 12 × 0.5, = 6 (square centimeter); a: the area of B is more than that of a: 6 square centimeter
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