There is a right angled trapezoid. The upper bottom is 3 / 5 of the lower bottom, and the lower bottom is reduced by 8 cm. It just turns into a square. What is the area of the original trapezoid?

-3 / 5) = 20 cm, so the bottom is 20 cm, 20-8 = 12 cm, so the bottom and height are 12 cm, area = (20 + 12)? 192 square cm

The area of a is 150 square centimeters more than that of B. the upper bottom of the trapezoid is 8 cm and the lower bottom is 28. Divide the trapezoid into two sides a and B with diagonal lines to find the area of the trapezoid?

If the height of a and B is equal, the area of a is 150 square centimeters more than that of B, and the bottom of a is 28-8 = 20 centimeters more than that of B, so the equation 1 / 2 * (28-8) * H = 150
The solution is h = 15
Trapezoid area s = 1 / 2 * (28 + 8) * 15 = 270

The two base lengths of the trapezoid are 2 cm and 8 cm respectively, and the two diagonal lengths are 6 cm and 8 cm respectively. What is the area of the trapezoid?
A 16 square centimeter B 24 square centimeter C 20 square centimeter D 48 square centimeter

The answer is B
This problem is mainly to find the height of the trapezoid. First, draw a picture and translate the 6 cm diagonal to the left by 2 cm. At this time, the 6 cm diagonal and 8 cm diagonal, as well as 10 cm of the bottom (the original 8 cm + 2 cm after translation) form a right triangle, (6 * 8) / 2 = 24, 24 / (10 / 5) = 4.8. In this way, we can find the height of the trapezoid. Let me not talk about it
All hands. Give me some points,

A trapezoid has an area of 100 square centimeters, a height of 10 centimeters, an upper bottom of 8 centimeters, and a lower bottom of () centimeters

Bottom = 100 × 2 △ 10-8 = 12 cm

There is a right angled trapezoid. The upper bottom is 3 / 5 of the lower bottom, and the lower bottom is reduced by 8 cm. It just turns into a square. What is the area of the original trapezoid?