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As shown in the figure, the quadrilateral ABCD is a trapezoid, CD ∥ AB, CD = Ao = 1, △ AOD is an isosceles right triangle, O is the midpoint of AB, try to find the area of the visual graph of the trapezoid ABCD placed horizontally
Because the quadrilateral ABCD is a trapezoid, CD ∥ AB, CD = Ao = 1, △ AOD is an isosceles right triangle, O is the midpoint of AB, so the area of the quadrilateral is: 1 + 22 × 1 = 32, because the ratio of the area of the plane figure and the area of the intuitive figure is 22, so the area of the horizontal intuitive figure of the trapezoid ABCD is: 3222 = 328
A map with a scale of 1:25000 is redrawn with a scale of 1:10000. The original map is 12.5cm long
The original 12.5cm corresponds to the actual 12.5 *: 25000 = 312500cm
After the change, 312500 / 10000 = 31.25cm
A map with a scale of 1:50000 is redrawn to a scale of 1:20000. How many centimeters should the distance of 2.5cm in the original map be drawn on the new map
13934452167 ,
2.5 × 50000 △ 20000 = 6.25 (CM)
What is the distance between Urumqi and Sanya on the map of China? What is the scale on the map?
In terms of distance measurement----
The actual distance from Urumqi to Sanya is 3514.6km
The scale is 1:50000000 (1cm: 500km)
The distance is 7.0292cm
A map with a scale of 1:50000 is redrawn to a scale of 1:20000. How many cm should the distance of 3:2 cm in the original map be drawn on the new map
For formula method and proportion solution, the specific formula will add points
3×50000=150000（cm）150000÷20000=7.5（cm）7.5÷3×2=5（cm）
A: the distance of 3:2 cm in the original map should be 5 cm in the new map
On a map with a scale of 1:40000, the distance between a and B is 12 cm. On a map with a scale of 1:30000, the distance between a and B is 12 cm
12 △ 1 / 40000 × 1 / 30000 = 16 cm
On a map with a scale of 1:40000, the distance between the two places is 5cm. If on a map with a scale of 1:25000, what is the distance between the two places?
5 △ 140000 = 200000 (CM), 200000 × 125000 = 8 (CM); a: the distance between the two places is 8 cm
The distance between Party A and Party B is 8 cm on a map of 1 / 60000 scale. If the map is drawn on a map of 1 / 40000 scale, the distance between Party A and Party B is 8 cm
What is the upper distance in centimeters
8 △ 1 / 60000 × 1 / 40000 = 12 cm
The distance between a and B is 4.8km. If you draw it on a map with a scale of 1:20000, how many centimeters should you draw?
Distance on the map = scale * field distance = 1:20000 * 4.8km = 24cm
The distance between Nanjing and Beijing is 900 kilometers. How many centimeters should be drawn on the map at the scale of 1:6000000?
15 cm. 900 km = 90 million cm, the calculation formula X: 90 million = 1:6000000, we know that x = 15
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- 1. The actual distance between Beijing and Nanjing is about 900 kilometers. On the map of China with a scale of 1:4500000, how many centimeters is the distance between the two places
- 2. In the eastern and western hemispheres with a scale of "1 cm in the map represents 1000 km in the field", the length of the equator should be
- 3. Beijing and Tianjin are about 120 kilometers apart. How many centimeters is the distance on the 1:600000 map? The distance between a and B is 15 cm. How many kilometers is the actual distance between a and B?
- 4. China has a total area of 9.6 million square kilometers. On the world map with a scale of 1:200000000, what is the area of China on the map? It's a process
- 5. On the drawing of 1:20000 scale, the width of a playground is 2 cm and the length is 3 cm. How many square meters is the actual area of the playground?
- 6. On the map with the scale of 1 / 2500000, the distance between the two cities is 10cm. If we discuss the distance between the two cities on a map, it is 3.125 Cm, what's the scale of that picture?
- 7. The actual distance between a and B is 150km. If it is 2.5cm drawn on a map, what is the scale of this map? A rectangular plot is 40 m long and 20 m wide. If the plot is drawn on a 40 cm long and 20 cm wide design drawing, what is the appropriate scale?
- 8. There are two maps with scales of 1:1000000 and 1:600000 respectively. On these two maps, the distance between a and B is 12 cm, and the distance between a and B is 12 cm
- 9. The perimeter of a rectangle is 88 meters. If the length is reduced by 1 / 12 and the width is increased by 2 meters, a square will be obtained. What is the square area? If you use the equation, please use X!!! Don't use X and Y!!! We haven't learned yet
- 10. The side length of a square is two seventh of a meter. How many decimeters is its perimeter? How many square decimeters is its area?
- 11. It is known that the bottom of a pyramid p-abcd is a square. How many right triangles are there at most among the four sides? How many pairs of planes are perpendicular to each other
- 12. The area of a trapezoid is 60 square centimeters, the bottom is 10 centimeters, and the height is 8 centimeters. How many centimeters is the top of the trapezoid
- 13. Please design three isosceles triangles of different shapes, so that it can be divided into two small isosceles triangles by a straight line, draw the divided figure and scale it
- 14. The area of a trapezoid is 16 square centimeters, and the sum of the top and bottom is 8 centimeters. How many centimeters is the height?
- 15. There is a right angled trapezoid. The upper bottom is 3 / 5 of the lower bottom, and the lower bottom is reduced by 8 cm. It just turns into a square. What is the area of the original trapezoid?
- 16. Two parallelograms A and B are overlapped. The area of the overlapped part is one fourth of a and one sixth of B. the area of a is 12 square centimeters
- 17. A. Two quadrilaterals of B are overlapped. The overlapped part is one fourth of a and one sixth of B. what is the simplest integer ratio of the area of quadrilateral B and a?
- 18. The area of the overlapping part of two rectangles is equivalent to one sixth of the area of the large rectangle and one fourth of the area of the small rectangle. What is the ratio of the large and small rectangles
- 19. As shown in the figure below, the area of the overlapping part of two rectangles is equal to 1 / 6 of the area of the large rectangle and 1 / 4 of the area of the small rectangle. Find two rectangles As shown in the figure below, the area of the overlapping part of two rectangles is equivalent to 1 / 6 of the area of the large rectangle and 1 / 4 of the area of the small rectangle, and the ratio of the area of the two rectangles is calculated. eleven thousand one hundred and eleven trillion and one hundred and eleven billion one hundred and eleven million one hundred and eleven thousand one hundred and eleven 1 ---------1 1111111111111111111111 1 1 1 1 1 111111111111111 1 11111111111111111111111111111
- 20. The overlapping part of two rectangles is equal to 1 / 6 of the area of large rectangle and 1 / 4 of the area of small rectangle