What are the words used to describe the difficulty in walking or the difficulty in walking

What are the words used to describe the difficulty in walking or the difficulty in walking

teeter
stumble along

It's strange that the idea doesn't conform to the reality. It's hard to walk because the road is not easy or the legs are not good

It's strange that an idea doesn't conform to reality
2. Describe the difficulty in walking or the difficulty in walking due to poor feet

Words to describe walking

Faltering, swinging, firm pace, vigorous pace, vigorous pace, creeping, three steps at the same time

The circumference of a rectangle is 12 cm, and its length and width are in whole centimeters. What is the possible area of the rectangle? Please write down all the possibilities

12/2 = 6
1.5 1
S = 5 * 1 = 5 cm2
2.4 2
S = 4 * 2 = 8 cm2

For a rectangle, the ratio of length to width is 14:5. If the length is reduced by 13 cm, the width is increased by 13 cm, and the area is increased by 18 square cm, the area of the original rectangle can be calculated

Let the length be x and the width be y, then the following two equations can be obtained
5X=14Y
(X-13）（Y+13）—18=XY
Solve the equation, get the value of X, y respectively, and then calculate the area

For a rectangle, the ratio of length to width is 14:5. If the length is reduced by 13 cm and the width is increased by 13 cm, the area will be increased by 18 square cm. The area of the original rectangle is? Square%

Let the original length be 14x and the width be 5x
(14x-13)(5x+13)=14x*5x+18
14x*15x+13*14x-13*5x-169=14x*5x+18
13*9x=187
x=187/117
The original length is 14 * (187 / 117) = 2618 / 117 cm;
Width 5 * (187 / 117) = 935 / 117 cm
The original rectangular area is 2618 / 117 * 935 / 117 ≈ 178.82 square centimeters

The ratio of the length to the width of a rectangle is 14:5. If the length is reduced by 13 cm and the width is increased by 13 cm, the area will be increased by 182 square cm. What is the area of the original rectangle?

Let the original rectangle be 14x in length and 5x in width. The equation (14x-13) × 13-5x × 13 = 182, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 182x-169-65x = 182, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp

The ratio of the length to the width of a rectangle is 14:5. If the length is reduced by 13 cm and the width is increased by 13 cm, the area will be increased by 182 square cm. What is the area of the original rectangle?

The length of the original rectangle is 14x and the width is 5x, and the length is 14x and the width is 5x. From the analysis of the figure, the equation (14x-13) × 13-5x13-5x13-5 x × 13 = 182, and the equation (14x-13-13) × 13-5x13-5x13-5x13 = 182, and the equation (14x-13-13) × 13-5x13-5x13 × 13 = 182, from the analysis of the figure, the equation equation (14x-13-13-13-13-13-13-5x13-5x13-5x13-5x13-5x13 × 13 = 182, which is obtained from the analysis from the analysis of the analysis of the analysis of the analysis of the analysis of the equation (the equation ((14x-13-13-13-13-13-13-13-13-13-5x13-5x13-5x13-5x13-5x13-5x13-5x13-5x13-5x13-5x13-5x13 = 13 = 13 = & nbsp; & nbsp; &If x = 3, the area of the original rectangle is (14 × 3) × (5 × 3), = 42 × 15, = 630 (square centimeter). A: the area of the original rectangle is 630 square centimeter