If the image of the function y = KX + B (K ≠ 0) is parallel to the straight line y = 2x + 3, and the intersection Y axis is at the point (0, - 1), then its analytical expression is______ ．

If the image of the function y = KX + B (K ≠ 0) is parallel to the straight line y = 2x + 3, and the intersection Y axis is at the point (0, - 1), then its analytical expression is______ ．

The graph of ∵ function y = KX + B (K ≠ 0) is parallel to the straight line y = 2x + 3, ∵ k = 2; substituting the point (0, - 1) into b = - 1, ∵ its analytical formula is: y = 2x-1

The graph of the function y = KX + B is parallel to the straight line y = 2x and passes through the point (0,3)

The image of ∵ function y = KX + B is parallel to the straight line y = 2x, ∵ k = 2. Substituting (0, 3) into y = 2x + B, we get: 3 = B, ∵ function analytic formula is: y = 2x + 3

The image of the first-order function YKX + B is parallel to the straight line y = 2x + 4 and passes through the point a (0,5)

The solution is parallel to the line y = 2x + 4 by the image of the secondary function y = KX + B
That is, k = 2
That is, the linear function y = 2x + B
By passing through point a (0,5),
That is, 5 = 2 * 0 + B
That is, B = 5
That is, the analytic formula of the function is y = 2x + 5

The image of the function y = KX + B passes through the point (2,3), which is flat and parallel to the straight line y = 2x + B. to find its analytical formula (need process)

∵ y = KX + B is parallel to y = 2x + B
The analytic expression of the function is y = 2x + B
∵ function image passes through points (2,3)
The point (2,3) is brought into the analytic expression
3=4+b
b=-1
The analytic formula of a function is y = 2x-1

It is known that the image of a function of degree y = KX + B is perpendicular to the image of y = - 2x + 3, and the analytic expression of the image of the function is obtained through points (6,4)

It is known that the image of a linear function y = KX + B is perpendicular to the image of y = - 2x + 3,
So k = - 1 / (- 2) = 1 / 2;
And passing through point (6,4)
4=(1/2)×6+b;
3+b=4;
b=1;
The analytic expression of this function graph is y = x / 2 + 1
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1.x²-xy+1/4y²-1 （a²+b²）²-8（a²+b²）

1.x²-xy+1/4y²-1
=（x-1/2y）²-1
=（x-1/2y＋1）（x-1/2y-1）
（a²+b²）²-8（a²+b²）
=（a²+b²）（a²+b²-8）

A rectangle with length x and width y is known. Its perimeter is 14. Its area is 10. Find the value of the integer x ^ 2Y + XY ^ 2

2(x+y)=14
xy=10
x+y=7
x^2y+xy^2=xy(x+y)=10*7=70

What is the linear equation of y = 2x + 1 with respect to Y-axis symmetry?
The answer is y = - 2x + 1

For a line with Y-axis symmetry,
That is to say, the value of Y is constant, and X is opposite to each other,
So, the new linear equation is
The value of Y is constant, and x times (- 1) is OK
y = 2* (-1)*x +1 =-2x +1

The general equation of the circle x ^ 2 + 2x + y ^ 2 = 0 about the y-axis symmetric circle

(x+1)²+y²=1
Center (- 1,0)
The center of a circle is (1,0) symmetric about the y-axis
So it's (x-1) ² + Y & #178; = 1
That is X & # 178; - 2x + Y & # 178; = 0

In the statement of curve C: x ^ 2 + y ^ 4 = 1: ① symmetry about origin (0,0); ② symmetry about X axis; ③ symmetry about straight line y = x; ④ C is a closed graph
⑤ The area is larger than π. Where is the correct serial number?

1. 2, 4, 5 correct number shape combination, take the square of Y as a whole, then get the circle with radius 1, and the square area of Y is greater than the area of circle 5 correct according to sketch 4 correct verification 1, 2 can bring negative X and negative y respectively according to the definition verification 3 can exchange X and y, obviously does not coincide with the function