As shown in the figure, it is known that the image of the inverse scale function Y1 = K1X and the image of the primary function y2 = k2x + B intersect at two points a and B, and a (2, n), B (- 1, - 2). (1) find the relationship between the inverse scale function and the primary function; (2) use the image to write directly when x is in what range, Y1 > Y2

As shown in the figure, it is known that the image of the inverse scale function Y1 = K1X and the image of the primary function y2 = k2x + B intersect at two points a and B, and a (2, n), B (- 1, - 2). (1) find the relationship between the inverse scale function and the primary function; (2) use the image to write directly when x is in what range, Y1 > Y2

(1) ∵ hyperbola Y1 = K1X, passing through point (- 1, - 2), ∵ K1 = - 1 × (- 2) = 2. ∵ hyperbola Y1 = 2x, passing through point (2, n), ∵ n = 1. From line y2 = k2x + B, passing through point a, B, we get 2k2 + B = 1 − K2 + B = − 2, and K2 = 1b = − 1

As shown in the figure, it is known that the image of inverse scale function Y1 = K1 / X intersects with the first-order function y2 = k2x + 1 at two points a and B, and AC is perpendicular to point C
The area is 1, and the tan angle AOC is 2
Find out the expression of inverse proportion function meeting once function
It's on the top 21 of 13

If the area of the triangle OAC is 1 and the tan angle AOC = 2
Then a (1,2) or (- 1,2) or (- 1, - 2) or (1, - 2)
So k = 2 or - 2
It's not right to substitute

As shown in the figure, the image of inverse scale function Y1 = K1X and positive scale function y2 = k2x intersect at a (- 1, - 3) and B (1,3). If K1X > k2x, then the value range of X is ()
A. - 1 ＜ x ＜ 0b. - 1 ＜ x ＜ 1C. X ＜ - 1 or 0 ＜ x ＜ 1D. - 1 ＜ x ＜ 0 or X ＞ 1

It can be seen from the figure that on the left side of point a, the value of the inverse proportional function is greater than that of the first-order function, at this time, X ＜ - 1; on the left side of point B, on the right side of the y-axis, the value of the inverse proportional function is greater than that of the first-order function, at this time, 0 ＜ x ＜ 1

As shown in the figure, it is known that the image of inverse scale function y = KX passes through point C (- 3,8), and the image of primary function passes through point C and intersects with X axis and Y axis at points a and B respectively, if OA = 3 and ab = BC. (1) find the analytic expression of inverse scale function; (2) find the length of AC and ob

(1) According to the meaning of the question, we can get: 8 = k − 3 (2 points) ｜ k = - 24. (3 points) ｜ the analytic formula of inverse proportional function y = − 24x. (4 points) (2) through point C as CE ⊥ X axis, the perpendicular foot is E (5 points) from C (- 3,8), we can see OE = OA = 3, ｜ AE = Ao + OE = 6, CE = 8, ｜ AC | = AE2 + CE2 = 62 + 82 = 10 (10 points)

As shown in the figure, given that point a is the intersection of the image with positive scale function y = x and the image with inverse scale function y = 2 / X in the first quadrant, point B is on the negative half axis of X axis, and OA = ob, then the area of △ AOB is ()
A.2
B. 2 √ 2
C.√2
D.2.√2

Because a (root 2, root 2), OA = 2, so B (- 2,0), so the bottom edge of △ AOB is 2, and the height is root 2, so s △ AOB = 1 / 2 × 2 × root 2 = root 2.. so C

As shown in the figure, the inverse scale function y = K / X and the first-order function y = 2x-1 are known, where the image of the inverse scale function passes through the point (2,1 / 2)
1) The analytic formula of inverse proportion function
2) The first quadrant of point a is known, and the coordinates of point a are calculated on the images of the above two functions at the same time
Under the condition of (2), is there a point P on the x-axis, which is a triangle and AOP is an isosceles triangle? If so, please write directly all the coordinates of P points that meet the conditions; if not, please explain the reason

1, because (2,1 / 2) is a point on y = K / x, so k = 1, y = 1 / X
2. Let the point a (x, y) in the first quadrant be the intersection of y = 1 / X and y = 2x-1. So 2x & # 178; - X-1 = 0. So x = 1. (x = - 1 / 2 does not fit the question). So a (1,1)
3, because OA = root 2, let P (m, 0) so m = root 2, M = - root 2, or M = 1.. that is p (root 2,0), P (- root 2,0) or P (1,0)

It is known that the line y = - 2x passes through the point P (- 2, a), and the symmetric point P 'of the point P about the Y axis is in the direction of the inverse scale function y = K / X (k is not equal to 0)
On the image, find the analytic expression of inverse scale function

Substituting (- 2, a) into y = - 2x, we get a = - 2 × (- 2) = 4, a = 4
The coordinates of ∵ P are (- 2,4), and the coordinates of ∵ p 'are (2,4)
Substituting P ′ (2,4) into the function y = KX, we get 4 = K2, ∩ k = 8,
The analytic expression of inverse proportion function is y = 8x

It is known that y is the inverse proportional function of X, when x = 3, y = 4. (1) write the analytic expression of the function where y is X. (2) find the value of X when y = 6

（1）
Let the analytic expression of inverse proportion function be y = K / X
Because when x = 3, y = 4
So 4 = K / 3
k=12
So the analytic formula is y = 12 / X
(2)
When y = 6
6=12/x
therefore
x=12/6=2

Y is the inverse proportion function of X. when x = 8, y = 12, the function relation is

y=k/x
12=k/8
k=96
y=96/x

Y is the inverse proportion function of X-2, when x = - 2, y = 1 / 2, find the function relation

Let y = K / X-2
By introducing (- 2,1 / 2) solution, k = - 2
So the function is y = - 2 / X-2