Find the vertex coordinates and axis of symmetry of the parabola y equal to the square of negative half x minus x plus three-thirds, and point out that when x takes any value, y increases with the increase of X, and when x takes any value, y decreases with the increase of X

Find the vertex coordinates and axis of symmetry of the parabola y equal to the square of negative half x minus x plus three-thirds, and point out that when x takes any value, y increases with the increase of X, and when x takes any value, y decreases with the increase of X

y=-1/2(x+1)+2
Vertex (- 1,2)
Axis of symmetry x = - 1
Decreasing when X-1

Make a straight line through the focus of the parabola y ^ 2 = 4x, intersect with the parabola at two points a and B, and the sum of their abscissa is equal to 5, then there are several such lines

The focus of Y ^ 2 = 4x is (1,0)
Let y = kx-k
And parabolic equations
k^2x^2-(2k^2+4)+k^2=0
The sum of abscissa is X1 + x2 = (2k ^ 2 + 4) / K ^ 2 = 5
It is found that 3K ^ 2 = 4 has two solutions
The calculation is correct
Full marks, ha ha