Given that the parabola y = a (x-1) 2 + H (a ≠ 0) intersects the X axis at two points a (x1, 0) and B (3, 0), then the length of line AB is () A. 1B. 2C. 3D. 4

Given that the parabola y = a (x-1) 2 + H (a ≠ 0) intersects the X axis at two points a (x1, 0) and B (3, 0), then the length of line AB is () A. 1B. 2C. 3D. 4

The vertex coordinates (1, H) of ∵ quadratic function y = a (x-1) 2 + H, - B2A = 1, then - BA = 2 and ∵ x2 = 3 ∵ X1 + x2 = X1 + 3 = 2, the solution is X1 = - 1 ∵ the length of AB = | x1-x2 | = | - 1) - 3 | = 4

What is the number of intersections between the parabola y = 3x ^ 2 + 5x and the coordinate axis?

y=3x^2+5x=X(3X+5)
Therefore, there are two intersections with the abscissa axis, namely (0,0) and (- 5 / 3,0)

How many intersections are there between the parabola y = 3x + 5x and the two axes?
A. 3 B.2 C.1 d.0 which one

If there are two roots in b-4ac > 0, then there are two intersections

How many points of intersection between the square of parabola y = 2x-5x + 3 and the coordinate axis?

y=2x²-5x+3=(2x-3)(x-1)
x=0,y=0-0+3
So three
That is, (3 / 2,0), (1,0) and (0,3)