The Quasilinear equation of parabola y = 2x2 is () A. 8x+1=0B. 8y+1=0C. 8y-1=0D. 4y+1=0

According to the meaning of the title, the standard equation of parabola is x2 = 12Y, ∧ P = 14, opening upward, ∧ quasilinear equation is y = - 18, that is, 8y + 1 = 0; therefore, B

The equation of parabola C is the Quasilinear equation of y = 2x ^ 2-2

First change to standard form
x^2=0.5(y+2)
It is easy to get x ^ 2 = 0.5y
The guide line is x = - 1 / 8
Then the image of x ^ 2 = 0.5 (y + 2) is x ^ 2 = 0.5y
Translation up 2 units of length
Therefore, the guide line remains unchanged, and it is still x = - 1 / 8

What is the Quasilinear equation of parabola y = - 1 / 2x & #

Known
2p=-1/2
So p = - 1 / 4
The guide line is
x=-p/2
So x = 1 / 8

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