The general solution formula of the first order linear differential equation (X-2) * dy / DX = y + 2 * (X-2) ^ 3, find the general solution of Y ∵(x-2)*dy/dx=y+2*(x-2)³     ==>(x-2)dy=[y+2*(x-2)³]dx         ==>(x-2)dy-ydx=2*(x-2)³dx         ==>[(x-2)dy-ydx]/(x-2)²=2*(x-2)dx         ==>d[y/(x-2)]=d[(x-2)²]         ==>y/(x-2)=(x-2)² +C & nbsp; (C is an integral constant) & nbsp; & nbsp; & nbsp; = = & gt; y = (X-2) & # 179; + C (X-2) & nbsp; & nbsp; & nbsp;; the general solution of the original equation is y = (X-2) & # 179; + C (X-2) & nbsp; (C is an integral constant)       How to get the following from the above formula?

The general solution formula of the first order linear differential equation (X-2) * dy / DX = y + 2 * (X-2) ^ 3, find the general solution of Y ∵(x-2)*dy/dx=y+2*(x-2)³     ==>(x-2)dy=[y+2*(x-2)³]dx         ==>(x-2)dy-ydx=2*(x-2)³dx         ==>[(x-2)dy-ydx]/(x-2)²=2*(x-2)dx         ==>d[y/(x-2)]=d[(x-2)²]         ==>y/(x-2)=(x-2)² +C & nbsp; (C is an integral constant) & nbsp; & nbsp; & nbsp; = = & gt; y = (X-2) & # 179; + C (X-2) & nbsp; & nbsp; & nbsp;; the general solution of the original equation is y = (X-2) & # 179; + C (X-2) & nbsp; (C is an integral constant)       How to get the following from the above formula?

(x-2)dy-ydx=(x-2)dy-yd(x-2)
Let's imagine that when we do differentiation for a division, D (f (x) / g (x)) = (GDF FDG) / (G ^ 2)
The form here is similar, so we can put together such a form:
[(X-2) dy yd (X-2)] / (X-2) ^ 2 [compare f (x) = y, G (x) = X-2]
=d[y/(x-2)]
The formula on the right is the inverse of D [(X-2) ^ 2]

It is known that the radius of a circle is 1.9 meters and the arc length is 0.994 meters

Center angle = arc length / radius
＝0.994/1.9
= 0.523 radians
= 30 degrees

General solution formula of first order linear differential equation
(X-2) * dy / DX = y + 2 * (X-2) ^ 3, find the general solution of Y
The answer is y = (X-2) ^ 3 + C * (X-2),

As a result of the (X-2) dy / DX (dx-2) as a result of the (X-2) dy / DX / DX / DX = y + 2 (X-2) dy = [y + 2 (X-2) (X-2) (X-2) dy [DY-2 (X-2) (X-2) (X-2) dy / dy / DX (dx-2) dy / dy / DX = 2 (X-2) DY-2 (X-2) DY-2 (X-2) (x-2-2) DY-2 (X-2) dy-y-2) (as the (X-2) DY-2) as the (X-2) dy (X-2) dy (X-2) DY-2) dy-2-2) is the (x-2-2) and the (x-2-2) is the last (X-2) and the last (X-2) and (as the (X-2) is the (X-2) is the (as C is the integral constant) = = > y = (x

Given an arc length of 45 cm with a center angle of 210 degrees, find the radius of the circle

(45 × 360 & # 186; / 210 & # 186;) / (2 × 3.14) = 12.28 (CM)
A: the radius of the circle is 12.28 cm

Zhang's income is 270 yuan. On the indifference curve of store X and y, the slope is dy / DX = 20 / y. The price of XY is 2 and 5 respectively. How much of X and y will Zhang consume

10 and 50, but you're wrong. The slope should be negative, not positive

If the radius of the circle is 100 cm, what is the length of the arc to which the central angle of the circle of 18 &

2X3.14X100X18/360=31.4

The slope of any point (x, y) on a curve C is dy / DX = 3-6x, and (1,6) is on the curve C
A: The equation for C has been solved as: y = 6 + 3x-3x ^ 2
B: Now find the area bounded by the C and X axes of the curve,

dy/dx=3-6Xy=3x-3x²+cx=1 y=c=6y=3x-3x²+6(2)y=3x-3x²+6=0x²-x-2=0(x-2)(x+1)=0x=-1 x=2∫(-1-->2)3x-3x²+6dx=3x²/2-3x³/3+6x|(-1-->2)=3x²/2-x³+6x|(-1-->2)=(6-8+12...

The center angle is 31.63, the radius is 15.7, and the chord length is 619

Should you write down the unit of each number? If you can't figure out the decimal point, how can I calculate it for you? Let me tell you something. The distance from chord to arc is the radius minus the distance from center to chord. You should know the distance from point to line. There are center angle, radius and chord length. Use the relationship between angle and edge in triangle to calculate the distance from point to chord, and use radius to reduce it!

Given the chord length 818, chord height 779, radius 819, find the center angle and arc length

Given the chord length L = 818, chord height h = 779, find the center angle A and arc length C
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*H*R+H^2+(L/2)^2
2*H*R=H^2+(L/2)^2
R=H/2+L^2/(8*H)
=779/2+818^2/(8*779)
=496.869
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((818/2)/496.869)
=110.8 degrees
=110.8*PI/180
=9339 radians
C=A*R
=1.9339*496.869
=906.889
Given the chord height h = 779 and radius r = 819, calculate the center angle A and arc length C
L=2*(R^2-(R-H)^2)^0.5
=2*(819^2-(819-779)^2)^0.5
=1636.045
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((1636.045/2)/819)
=174.4 degrees
=174.4*PI/180
=3.044 radians
C=A*R
=3.044*819
=2492.9
Given the chord length L = 818 and radius r = 819, calculate the center angle A and arc length C
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((818/2)/819)
=59.919 degrees
=59.919*PI/180
=1.0458 radians
C=A*R
=1.0458*819
=855.45

What is the sector area formula?

The area formula of sector: s sector = (LR) / 2 (L is the arc length of sector)
Or s sector = (n / 360) π R ^ 2 (n is the degree of the center angle)