![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Let y = f (secx) and the derivative of F (x) be equal to x, then what is dy / DX | x = π / 4 Please write down the specific steps, thank you~
y=f(secx)
y'=f'(secx)*secxtanx
=sec²xtanx
therefore
dy/dx | x=π/4
=sec²π/4tanπ/4
=2
Let f (U) be differentiable, y = f (secx ^ 2), what is dy / DX
If the title is secx & # 178;, let u = secx & # 178;, then y = f (U), we can get dy / DX = (dy / DU) * (DU / DX) = f '(U) * 2x * secx & # 178; * TaNx & # 178; = 2x * secx & # 178; * TaNx & # 178; * f' (secx & # 178;) if the title is sec & # 178; X, let u = sec & # 178; X
Y = f (secx), f '(x) = x, then dy / dx|x = π / 4=__ The answer is equal to 2. I don't know how to calculate the poor foundation. I hope the talent can help me write out the steps!
The score is not enough. I have to take the advanced mathematics exam three times at the weekend. T.T
dy/dx=f'(secx)*tanx*secx
Because f '(x) = x, f' (secx) = secx
arcsinx-x
dy/dx=sec^x*tanx
When x = π / 4, = 2
The general solution of Y given dy / DX = Xe ^ x
y=（x-1）e^x+C
RELATED INFORMATIONS
- 1. dy/dx+(e^((y^2)+x))/y=0 How to put C in solving differential equation
- 2. Given the function f (x) = ax ^ 2 - (a + 2) x + LNX, when a = 1, find the tangent equation of the curve y = f (x) at the point (1, f (1))
- 3. Finding the original function of (lnx-1) / (x ^ 2)
- 4. The primitive function of (f '(LNX)) / 3x
- 5. Monotone decreasing interval of function y = 8x ^ 2-lnx
- 6. Given the function f (x) = (LNX + a) / X (a ∈ R) (1), find the monotone interval of function f (x) (2) when f (x) ≤ 1 Given function f (x) = (LNX + a) / X (a ∈ R) (1) Find the monotone interval of function f (x) (2) when f (x) ≤ 1, find the value range of real number a
- 7. （ln(1+x)）^2-X^2/(1+x)
- 8. It is proved that when x ≠ 0, ex ＞ 1 + X, f (x) = ex-1-x
- 9. Lagrange's Mean Value Theorem Why is theta between 0 and 1?
- 10. A proof of Lagrange's mean value theorem Verification: when x > 0, there is 1 / (1 + x)
- 11. General solution of dy / DX = y (Y-1)
- 12. General solution of differential equation DX / dy equal to 1 / X
- 13. Dy / DX + (2 / x) y = - x when y (2) = 0,
- 14. How to find y = e ^ sin2x dy
- 15. The special solution of dy / DX = e ^ (x-y-2), y (0) = 0
- 16. Given a ∈ [0, π / 2], then when ∫ a reaches the maximum value of 0 (cosx SiNx) DX, a=
- 17. Quasilinear equation of parabola y = 2 (x square)
- 18. Find ∫ l DX dy + ydz, where l is the directed closed broken line ABCA, where a, B and C are (1,0,0), (0,1,0), (0,0,1) respectively
- 19. What is ∫ = dy / DX? How to apply it? What are the related formulas?
- 20. The general solution formula of the first order linear differential equation (X-2) * dy / DX = y + 2 * (X-2) ^ 3, find the general solution of Y ∵(x-2)*dy/dx=y+2*(x-2)³ ==>(x-2)dy=[y+2*(x-2)³]dx ==>(x-2)dy-ydx=2*(x-2)³dx ==>[(x-2)dy-ydx]/(x-2)²=2*(x-2)dx ==>d[y/(x-2)]=d[(x-2)²] ==>y/(x-2)=(x-2)² +C & nbsp; (C is an integral constant) & nbsp; & nbsp; & nbsp; = = & gt; y = (X-2) & # 179; + C (X-2) & nbsp; & nbsp; & nbsp;; the general solution of the original equation is y = (X-2) & # 179; + C (X-2) & nbsp; (C is an integral constant) How to get the following from the above formula?