Finding the original function of (lnx-1) / (x ^ 2)

Finding the original function of (lnx-1) / (x ^ 2)


∫(lnx-1)dx/(x^2)
=∫lnxdx/x^2-∫dx/x^2
= -∫lnxd(1/x)+1/x
=(-1/x)lnx+∫(1/x^2)dx+1/x
=(-1/x)lnx+C



What is the LNX / X primitive function?
 


(1 / x) DX = dlnx, the original function of LNX / X is (1 / 2) ln ^ 2 (x) + C



What is the original function of y = LNX / x


∫lnx/xdx
=∫lnxdlnx
=(lnx)^2/2+C



1 / X is the original function of LNX, right


No
LNX is the original function of 1 / X