The following pairs of functions are the same function is () (a) f (x) = x, G (x) root x square (b) f (x) = x, G (x) = (root x) square (C) F (x) = x + 1, G (x) = x squared-1 / X-1 (d) f (x) = INX & # 710; 3, G (x) = 3 INX reason:

The following pairs of functions are the same function is () (a) f (x) = x, G (x) root x square (b) f (x) = x, G (x) = (root x) square (C) F (x) = x + 1, G (x) = x squared-1 / X-1 (d) f (x) = INX & # 710; 3, G (x) = 3 INX reason:

The same is: (d) f (x) = INX & # 710; 3, G (x) = 3 INX
(same domain, x > 0, LNX ^ 3 = 3lnx)
A. F (x) = x is a real number, G (x) = root x ^ 2 > 0
B. The definition field is different from the value field
C. Domain is different

The definition field of multiple choice function y = root log 1 / 2 (3-x) + 1 is ()
A. [1,3] B. (1,3) C. [1,3) d. (1,3) what to choose? I'm not good at this. I'll write out the solution,

C. [1,3] the number under the root sign must be greater than or equal to o, and the real number is greater than 0

The domain of definition of function y = in (X & # 710; 2-4) is () (a) [- 2,2] (b) (- ∞, - 2) ∪ [2, + ∞)
（C）（-2,2） （D）（-∞,-2）∪（2,+∞）

D

Calculate the following definite integral: ∫ upper limit 1, lower limit 0 (Xe ^ x) DX; ∫ upper limit 1E, lower limit 0xlnxdx; process!

∫(0→1) xe^x dx = ∫(0→1) x d(e^x)
= xe^x - ∫(0→1) e^x dx
= [(1)e^(1) - (0)e^(0)] - e^x
= e - [e^(1) - e^(0)]
= e - e + 1
= 1
∫(0→e) xlnx dx = ∫(0→e) lnx d(x²/2)
= (1/2)x²lnx - (1/2)∫(0→e) x² d(lnx)
= [(1/2)(e²)ln(e) - (1/2)(0)] - (1/2)∫(0→e) x dx
= (1/2)e² - (1/2)(x²/2)
= (1/2)e² - (1/4)(e² - 0)
= (1/4)e²