Find the general solution of the differential equation (1 + e ^ (- X / y) YDX + (Y-X) dy = 0!

Find the general solution of the differential equation (1 + e ^ (- X / y) YDX + (Y-X) dy = 0!

If we divide by YDY, we can get [1 + e ^ (- X / y)] DX / dy = - (1-x / y) (1) let X / y = P, then x = py; if DX / dy = DP / dy * y + P is carried into (1), we can get [1 + e ^ (- P)] (ydp / dy + P) = - (1-p) = P-1, and simplify to [1 + e ^ P] * ydp / dy = - [

General solution of differential equation (2Y + x) dy YDX = 0

dx/dy=(2y+x)/y=2+x/y
Let X / y = u, x = Yu, X '= u + Yu'
u+yu'=2
yu'=2-u
du/(2-u)=dy/y
ln(2-u)=lny+C1=ln(e^C1*y)
2-u=Cy
2-x/y=Cy

What is the general solution of the differential equation YDX + (X-Y) dy = 0,

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What is the general solution of the differential equation (x + y) dy YDX = 0?