∫0a（3x2-x+1）dx=______ ．

∫0a（3x2-x+1）dx=______ ．

∫ 0A (3x2-x + 1) DX = (x3-12x2 + x) | 0A = a3-12a2 + a

How to calculate the indefinite integral of X + 2 / x?
Where does 1-2 / (x + 2) 1 minus 2 come from
Also, do you want to use partial integral or exchange element?

First change the formula to 1-2 / (x + 2) [this will change], and then change the following DX to D (x + 2), because DX and D (x + 2) are equivalent. At this time, it is a constant and an integral with (x + 2) variable. You will get it. Remember to add the constant C
X / (x + 2) = (x + 2-2) / (x + 2) = 1-2 / (x + 2). This reduction method is often used

How to calculate the indefinite integral of 1 / (x ^ 4-2x ^ 2 + 1)?