How to calculate indefinite integral (x ^ 4-2) / (x ^ 2 + 1) DX?

How to calculate indefinite integral (x ^ 4-2) / (x ^ 2 + 1) DX?


A:
∫(x^4-2)/(x²+1) dx
=∫ (x^4-1-1)/(x²+1) dx
=∫ (x²-1) -1/(x²+1) dx
=x³/3-x-arctanx+C



Calculation of indefinite integral ∫ X / (x ^ 2 + 5) DX by means of integral substitution


∫x/(x^2+5)dx
= (1/2)∫dln(x^2+5)
= (1/2)ln(x^2+5) + C



∫ (4 + X / 4-x) DX to calculate indefinite integral


3x-4ln（x-4）

Elden Ring Premiere

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